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author | Timothy Pearson <[email protected]> | 2011-12-03 11:05:10 -0600 |
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committer | Timothy Pearson <[email protected]> | 2011-12-03 11:05:10 -0600 |
commit | f7e7a923aca8be643f9ae6f7252f9fb27b3d2c3b (patch) | |
tree | 1f78ef53b206c6b4e4efc88c4849aa9f686a094d /tde-i18n-en_GB/docs/tdeedu/kstars/leapyear.docbook | |
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diff --git a/tde-i18n-en_GB/docs/tdeedu/kstars/leapyear.docbook b/tde-i18n-en_GB/docs/tdeedu/kstars/leapyear.docbook new file mode 100644 index 00000000000..cf855c7534b --- /dev/null +++ b/tde-i18n-en_GB/docs/tdeedu/kstars/leapyear.docbook @@ -0,0 +1,58 @@ +<sect1 id="ai-leapyear"> +<sect1info> +<author +><firstname +>Jason</firstname +> <surname +>Harris</surname +> </author> +</sect1info> +<title +>Leap Years</title> +<indexterm +><primary +>Leap Years</primary> +</indexterm> +<para +>The Earth has two major components of motion. First, it spins on its rotational axis; a full spin rotation takes one <firstterm +>Day</firstterm +> to complete. Second, it orbits around the Sun; a full orbital rotation takes one <firstterm +>Year</firstterm +> to complete. </para +><para +>There are normally 365 days in one <emphasis +>calendar</emphasis +> year, but it turns out that a <emphasis +>true</emphasis +> year (&ie;, a full orbit of the Earth around the Sun; also called a <firstterm +>tropical year</firstterm +>) is a little bit longer than 365 days. In other words, in the time it takes the Earth to complete one orbital circuit, it completes 365.24219 spin rotations. Do not be too surprised by this; there is no reason to expect the spin and orbital motions of the Earth to be synchronised in any way. However, it does make marking calendar time a bit awkward.... </para +><para +>What would happen if we simply ignored the extra 0.24219 rotation at the end of the year, and simply defined a calendar year to always be 365.0 days long? The calendar is basically a charting of the Earth's progress around the Sun. If we ignore the extra bit at the end of each year, then with every passing year, the calendar date lags a little more behind the true position of Earth around the Sun. In just a few decades, the dates of the solstices and equinoxes will have drifted noticeably. </para +><para +>In fact, it used to be that all years <emphasis +>were</emphasis +> defined to have 365.0 days, and the calendar <quote +>drifted</quote +> away from the true seasons as a result. In the year 46 <abbrev +>BCE</abbrev +>, Julius Caeser established the <firstterm +>Julian Calendar</firstterm +>, which implemented the world's first <firstterm +>leap years</firstterm +>: He decreed that every 4th year would be 366 days long, so that a year was 365.25 days long, on average. This basically solved the calendar drift problem. </para +><para +>However, the problem wasn't completely solved by the Julian calendar, because a tropical year isn't 365.25 days long; it's 365.24219 days long. You still have a calendar drift problem, it just takes many centuries to become noticeable. And so, in 1582, Pope Gregory XIII instituted the <firstterm +>Gregorian calendar</firstterm +>, which was largely the same as the Julian Calendar, with one more trick added for leap years: even Century years (those ending with the digits <quote +>00</quote +>) are only leap years if they are divisible by 400. So, the years 1700, 1800, and 1900 were not leap years (though they would have been under the Julian Calendar), whereas the year 2000 <emphasis +>was</emphasis +> a leap year. This change makes the average length of a year 365.2425 days. So, there is still a tiny calendar drift, but it amounts to an error of only 3 days in 10,000 years. The Gregorian calendar is still used as a standard calendar throughout most of the world. </para> +<note> +<para +>Fun Trivia: When Pope Gregory instituted the Gregorian Calendar, the Julian Calendar had been followed for over 1500 years, and so the calendar date had already drifted by over a week. Pope Gregory re-synchronised the calendar by simply <emphasis +>eliminating</emphasis +> 10 days: in 1582, the day after October 4th was October 15th! </para> +</note> +</sect1> |